16-28y+12y^2=1

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Solution for 16-28y+12y^2=1 equation:


Simplifying
16 + -28y + 12y2 = 1

Solving
16 + -28y + 12y2 = 1

Solving for variable 'y'.

Reorder the terms:
16 + -1 + -28y + 12y2 = 1 + -1

Combine like terms: 16 + -1 = 15
15 + -28y + 12y2 = 1 + -1

Combine like terms: 1 + -1 = 0
15 + -28y + 12y2 = 0

Factor a trinomial.
(5 + -6y)(3 + -2y) = 0

Subproblem 1

Set the factor '(5 + -6y)' equal to zero and attempt to solve: Simplifying 5 + -6y = 0 Solving 5 + -6y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -6y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -6y = 0 + -5 -6y = 0 + -5 Combine like terms: 0 + -5 = -5 -6y = -5 Divide each side by '-6'. y = 0.8333333333 Simplifying y = 0.8333333333

Subproblem 2

Set the factor '(3 + -2y)' equal to zero and attempt to solve: Simplifying 3 + -2y = 0 Solving 3 + -2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2y = 0 + -3 -2y = 0 + -3 Combine like terms: 0 + -3 = -3 -2y = -3 Divide each side by '-2'. y = 1.5 Simplifying y = 1.5

Solution

y = {0.8333333333, 1.5}

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